Question

If a car requires $30$ seconds to acceleration from zero to $90$ km per hour its average acceleration is most nearly.

Answer 1

If the vehicle changed its velocity (velocity defined by physics is where both a magnitude and a direction are needed to define it), from zero (0) km/h to ninety (90) km/h , we could use the equation for acceleration, which is:

$Acceleration\left(a\right)=\frac{changeinvelocity}{changeintime}$

$Changeinvelocity=v(v_{final}-v_{initial})$

$Changeintime=t(t_{final}-t_{initial})$

We would need to change km/h into m/s

$v=\left(25m/s\right)-\left(0m/s\right)=25m/s$

$t=\left(15s\right)-\left(0s\right)=15seconds$

$Acceleration\left(a\right)=\frac{25m/s}{15seconds}$

$Acceleration\left(a\right)=1.66666667m/s^2$