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Question

If a car travelling at 40 m/s is to be brought to rest in a distance of 100 m, then its retardation should be

A
6 m/s2
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B
8 m/s2
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C
10 m/s2
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D
9 m/s2
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Solution

The correct option is B 8 m/s2
As per the question, final velocity of the car will be v=0
Given, initial velocity u=40 m/s, distance s=100 m
As per 3rd equation we have
v2u2=2as
0402=2a×100 a=1600200=8 m/s2
Thus, the retardation of the car is 8 m/s2

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