Question

If a Carnot engine is working between steam point and ice point, then its efficiency will be:

• A. 24.9%
• B. 25.7%
• C. 26.8%
• D. 28.8%

Answer 1

The correct option is C 26.8%

Ice point $=0°C=273K$

Steam point $=100°C=372K$

$\eta =(1-\frac{T_2}{T_4})\times 100=(1-\frac{273}{373})\times 100=\frac{100\times 100}{373}=26.80\%$