If a cell with O.P. 10 bars and T.P. 4 bars is connected to cells B, C and D having O.P. and T.P. 4 and 4, 10 and 5 and 7 and 3 bars respectively, the flow of water will be

C to A, B and D

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B to A, C and D

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A to D, B and C

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A to B, C and D

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Solution

The correct option is C B to A, C and D
Diffusion pressure deficit (DPD) represents the absorbing capacity of the cell. It is also called as suction pressure. It is the difference between osmotic pressure (OP) and total pressure (TP), that DPD = OP - TP. When DPD is zero, there is no movement of water. Water moves from lower DPD to higher DPD. In the given problem, DPD of cell A is OP - TP = 10 - 4 = 6. Similarly, DPD of cell B, C and D are 0, 5 and 4. Hence, flow of water will be from B to A, C and D as B is having hte lowest DPD, that is zero.
Thus, the correct answer is option B.

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