If a certain quantity of electricity liberates 11.2 litres of oxygen at S.T.P. If same quantity of electricity liberates 60 grams of a tetravalent element, the atomic weight of the element is:

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120

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180

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Solution

The correct option is B 120
$11.2 l i t e r s O_{2} \Rightarrow \frac{11.2}{22.4} m o l o f O_{2}$

$∴ m o l e s o f O_{2} = 0.5$

$4$ moles of $e^{-}$ liberate $1$ mole of $O_{2}$

$∴ m o l e s o f e^{-} = 4 \times 0.5$

$= 2 m o l e s$

$M^{4 +} + 4 e^{-} \to M$

4 moles of $e^{-}$ give 1 mole of metal

$∴ m o l e s o f m e t a l = \frac{2}{4} = 0.5 m o l e$

$0.5 = \frac{60}{M . W}$

$∴ M . W = 120 g$

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