Question

If a charge of $1.6\times {10}^{-19}$ C flows per second through any cross-section of any conductor, the current will be:

• A. $2.56\times {10}^{-19}$A
• B. $6.25\times {10}^{-19}$A
• C. $1.6\times {10}^{-19}$A
• D. $3.2\times {10}^{-19}$A

Answer 1

The correct option is C $1.6\times {10}^{-19}$A

The current is defined as the rate of flow of charged particles.
i.e.
$i=\frac{Q}{t}$
here,
$Q=1.6\times {10}^{-19}C$
$t=1s$
Hence,
$i=\frac{1.6\times {10}^{-19}C}{1s}=1.6\times {10}^{-19}A$