If a charge Q is distributed on the concentric hollow spheres of radii r and R(> r) such that their surface densities are equal then the potential at their common centre is
A
Q(R2+r2)4πϵ0(R+r)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
QRR+r
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Q(R+r)4πϵ0(R2+r2)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is DQ(R+r)4πϵ0(R2+r2) q1+q2=Q and q14πr2=q24πR2 (given) q1=Qr2R2+r2 and q2=QR2R2+r2 Potential at common centre 14πϵ0[Qr2(R2+r2)r+QR2(R2+r2)R]=Q(R+r)4πϵ0(R2+r2)