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Standard XII

Physics

Electric Field

If a charged ...

Question

If a charged body experiences a force of repulsion of magnitude $F$ from a charge of $q_{0}$ , the electric field $E$ of the charged body at a point lying not in between the $2$ charges but on the same line joining two charges, is :

\frac{F}{q_{0}}

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< \frac{F}{q_{0}}

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> \frac{F}{q_{0}}

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Solution

The correct option is D $> \frac{F}{q_{0}}$
Electric field of a charged body due to charge: $q_{0} = E_{0} = \frac{F}{q_{0}}$
But the electric field of the charged body at a not in between two charges means the sum of field due to all point charges,i.e., $E = \frac{F}{q_{0}} + \sum_{i} \frac{F}{q_{i}}$
So, $E > \frac{F}{q_{0}}$

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If a charged body experiences a force of repulsion of magnitude F from a charge of q0, the electric field E of the charged body at a point lying not in between the 2 charges but on the same line joining two charges, is :

The correct option is D >Fq0Electric field of a charged body due to charge: q0=E0=Fq0But the electric field of the charged body at a not in between two charges means the sum of field due to all point charges,i.e., E=Fq0+∑iFqiSo, E>Fq0

If a charged body experiences a force of repulsion of magnitude $F$ from a charge of $q_{0}$ , the electric field $E$ of the charged body at a point lying not in between the $2$ charges but on the same line joining two charges, is :