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Question
If a charged particle enters perpendicularly into the uniform magnetic field then its
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Solution
Force on charge particle q moving with velocity →Vin uniform magnetic field is given by
→F=q(→V×→B)As this →Fis perpendicular to →V as well as →B,the particle starts moving in the circular path.
As force and displacement are perpendiculars, the net work done will be zero and kinetic energy does not change.
But as it moves in a circular path, the direction of velocity changes periodically, so the momentum will also change.
As the charged particle enters perpendicular to the magnetic field, the force will act perpendicular to the velocity.
Hence, option (a) is the correct answer.
→F=q(→V×→B)As this →Fis perpendicular to →V as well as →B,the particle starts moving in the circular path.
As force and displacement are perpendiculars, the net work done will be zero and kinetic energy does not change.
But as it moves in a circular path, the direction of velocity changes periodically, so the momentum will also change.
As the charged particle enters perpendicular to the magnetic field, the force will act perpendicular to the velocity.
Hence, option (a) is the correct answer.
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