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Question

If a chord of the circle x2+y2=8 makes equal intercepts of length a on the coordinate axes, then

A
|a|<8
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B
|a|<42
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C
|a|<4
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D
|a|>4
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Solution

The correct option is D |a|<4
Since the chord makes equal intercepts of length a on the coordinate aces.
So, its equation can be written as x±y=±a
This line meets the given circle at two distinct points.
So, length of the perpendicular from the center (0,0) of the given circle must be less than the radius
i.e ±a2<8a2<16|a|<4

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