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Question

If a circle intersects the parabola y2=4ax at point A(at21,2at1),B(at22,2at2),C(at23,2at3),D(at24,2at4), then t1+t2+t3+t4+t4 is

A
1
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B
1
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C
0
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D
2
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Solution

The correct option is C 0
Given, Parabola y2=4ax

Let the equation of circle be x2+y2+2gx+2fy+c=0

Since (at2,2at) lies on parabola then, (say general pont)

(at2)2+(2at)2+2g(at2)+2f(2at)+c=0

a2t4+4a2t2+2agt2+4aft+c=0

This equation is of fourth degree,
Therefore sum of roots os above equation is 0., As the coefficient of t3 is 0.

t1+t2+t3+t4=0

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