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Question

If a circle whose centre is (1,-3) touches the line 3x-4y-5=0, then the radius of the circle is

A

2

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B

4

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C

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D

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Solution

The correct option is A
2

Radius $= ∣ ∣ \frac{3 + 12 - 5}{5} ∣ ∣$
$= 2$

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Similar questions

If a circle whose centre is (1, –3) touches the line 3x – 4y –5 = 0, then the radius of the circle is

Q. If a circle whose centre is (1, –3) touches the line 3x – 4y –5 = 0, then the radius of the circle is

x + 2 y = 3

2 x + y = 3

touches a circle whose centre lies on a line

3 x + 4 y = 5,

then possible centres of circle are

Q. The centre of the circle, whose radius is

5

and which touches the circle

x^{2} + y^{2} - 2 x - 4 y - 20 = 0

(5, 5)

3 x - 4 y - 8 = 0

divides the circumference of the circle with centre

(2, - 3)

1 : 2

. Then, the radius of the circle is:

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