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If a circle whose centre is (1, –3) touches the line 3x – 4y –5 = 0, then the radius of the circle is

A

2

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B

4

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C

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D

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Solution

The correct option is A 2
Radius = perpendicular distance from (1, -3) to the given line 3x - 4y - 5 = 0.
i.e. $∣ ∣ ∣ \frac{3 + 12 - 5}{\sqrt{5^{2}}} ∣ ∣ ∣ = 2.$

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