Question

If a code if $J=17$ and $DOG=47$ , then MICE can be coded as

• A. 30
• B. 45
• C. 58
• D. 65

Answer 1

The correct option is C 58

J is at the 10th place in alphabetic series.

$17=10+7=$ position of $J+7$.

$DOG=47$

D O G

$\downarrow$ $\downarrow$ $\downarrow$

4 15 7

$D+7+O+7+G=4+7+15+7+7+7=47$.

After every letters the number 7 is being added.

So, $MICE=13+7+9+7+3+7+5+7=58$.

Hence, option C is correct.