If a coin is tossed 3 times, what is the probability of getting atleast one tail?

A. $\frac{1}{8}$

B.$\frac{5}{8}$

C.$\frac{1}{4}$

D.$\frac{7}{8}$

The correct option is D $\frac{7}{8}$

Given, a coin is tossed 3 times. Total possible outcomes = {HHH, HHT, HTT, HTH, THH, TTH, THT, TTT} (where H = Heads, T= Tails) = 8 Number of favourable outcomes (getting at least one tail) = {HHT, HTT, HTH, THH, TTH, THT, TTT} Out of 8 possible outcomes, there are 7 favourable outcomes. We have, Probability of an event, P(E) = $\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}$ $\Rightarrow$ P (getting atleast one tail) = $\frac{7}{8}$ Therefore, the probability of getting atleast one tail is $\frac{7}{8}$ .