Question

If a coin is tossed twice, is the probability of getting two heads equal to the probability of getting no heads at all? What are the two probabilities in the order of

i) Getting two heads

ii) Getting no heads

• A. No; ;
• B. No; ;
• C. Yes ;
• D. Yes ;

Answer 1

The correct option is C

Yes ;

$$\begin{array}{ccc}1sttoss& & \\ 2ndtoss& H& T\\ H& HH& HT\\ T& TH& TT\end{array}$$

Total outcome = 4 { H H, H T, T H, T T}

P(H H) = $\frac{1}{4}$

P(no heads at all) = P (T T) = $\frac{1}{4}$

∴ P(H H) = P(two heads) = P(no heads at all) = $\frac{1}{4}$