wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If a complex number then |z| would be
z=2032+30322314232

A
0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1210
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0
z=2032i+3023+32i14232i

=20(3+2i)(3)2(2i)2+30(2332i)(23)2(32i)214(23+2i)(23)2(2i)2

=20(3+2i)530(23+32i)3014(23+2i)14

=43+42i2332i232i=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Properties
ENGINEERING MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon