If a compound AB dissociates to the extent of 75% in an aqueous solution, the molality of the solution which shows a 1.82 K rise in the boiling point of the solution is
(Given: Molal elevation constant for water =0.52K kg mol−1)
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Solution
AB→A++B−1−ααα
Given that α=3/4 N=2 i=[1+(2−1)α]
The rise in boiling point is ΔTb=i×Kb×m ⇒1.82=[1+(2−1)3/4]×0.52×m ⇒m=1.820.52×74=7.283.64=2 ⇒m=2 mol/kg