If a compound is made of sodium, carbon, and oxygen and their % composition are 43.4%, 11.3%, 45.3% respectively. What is the chemical formula of the compound?

$N a_{2} C O_{3}$

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$N a_{3} C O_{2}$

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$N a C O$

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$N a H C O_{3}$

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Solution

The correct option is A
$N a_{2} C O_{3}$

Element Percentage R.A.M No. of atoms(rounded)

Na 43.4% 23 $\frac{43.3}{23} = 1.882 2$

C 11.3% 12 $\frac{11.3}{12} = 0.942 1$

O 45.3% 16 $\frac{45.3}{16} = 2.831 3$

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Similar questions

N a = 23 C = 12, O = 16

Determine the empirical formula of a compound containing 43.3% sodium, 11.3% Carbon, 45.28% Oxygen by mass

C H_{2} O

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