Question

If a compound $MC{l}_3$ is hydrolysed and if there is an orange turbidity, then $MC{l}_3$ is $BiC{l}_3$ and when there is white turbidity, then $MC{l}_3$ is $SbC{l}_3$.
Answer whether the above statement is true or false.
If true enter 1, else enter 0.

Answer 1

If $MC{l}_3$ is hydrolysed and if there is an orange turbidity, then $MC{l}_3$ Is $SbC{l}_3$ and when there is white turbidity, then $MC{l}_3$ is $BiC{l}_3$.

$SbC{l}_3+H_{2}O\to SbOCl+2HCl$ (orange turbidity)

$BiC{l}_3+H_{2}O\to BiOCl+2HCl$ (white turbidity

Hence, the correct answer is 0.