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B
34≤A≤1
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C
1316≤A≤1
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D
12≤A≤1
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Solution
The correct option is B34≤A≤1 A=cos2θ+sin4θ =sin4θ−sin2θ+1 =sin2θ(sin2θ−1)+1 =1−sin2θcos2θ A=1−(sin2θ)24 Range of (sin2θ)2 is [0,1] ∴ The range of A is [34,1]