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Question

If a cos3 α+3a cos α sin2 α=m and a sin3 α +3a cos2 α sin α=n, then (m+n)23+(mn)23 is equal to


A

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B

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C

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D

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Solution

The correct option is C


From the given relations, we get m+n=a cos3α+3a cos α sin2α+3a cos2 α sin α+a sin3α =a(cosα+sinα)3
Similarly mn=a(cos αsin α)3 (m+n)23+(mn)23=a23[(cos α+sin α)2+(cos αsin α)2]


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