If a=cosα+isinα, b=cosβ+isinβ,
c=cosγ+isinγ and bc+ca+ab=1,Then
cos(β-γ)+cos(γ-α)+cos(α-β) is equal to
1
bc=cosβ+isinβcosγ+isinγ×cosγ−isinγcosγ−isinγ
⇒bc=cos(β−γ)+isin(β−γ).....(i)
Similarly, ca=cos(γ−α)+isin(γ−α).......(ii)
And ab=cos(α−β)+isin(α−β).......(ii)
Equating real and imaginary parts,
cos(β−γ)+cos(γ−α)+cos(α−β)=1