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Question

If a=cosα+isinα, b=cosβ+isinβ,

c=cosγ+isinγ and bc+ca+ab=1,Then

cos(β-γ)+cos(γ-α)+cos(α-β) is equal to


A

3/2

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B

-3/2

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C

0

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D

1

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Solution

The correct option is D

1


bc=cosβ+isinβcosγ+isinγ×cosγisinγcosγisinγ

bc=cos(βγ)+isin(βγ).....(i)

Similarly, ca=cos(γα)+isin(γα).......(ii)

And ab=cos(αβ)+isin(αβ).......(ii)

Equating real and imaginary parts,

cos(βγ)+cos(γα)+cos(αβ)=1


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