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Question

If acosθ+bsinθ=m and asinθbcosθ=n, then a2+b2 equals

A
m+n
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B
mn
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C
mn
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D
m2+n2
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Solution

The correct option is D m2+n2
Squaring m and n and adding them, we get
m2+n2=(acosθ+bsinθ)2+(asinθbcosθ)2
=a2cos2θ+b2sin2θ+2absinθcosθ+a2sin2θ+b2cos2θ2absinθcosθ
=a2cos2θ+b2sin2θ+a2sin2θ+b2cos2θ
=a2(cos2θ+sin2θ)+b2(cos2θ+sin2θ)
=a2+b2

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