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Question

If acosθ+bsinθ=m and asinθbcosθ=n, then a2+b2 = ____

A
m2n2
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B
m2n2
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C
n2m2
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D
m2+n2
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Solution

The correct option is D m2+n2
Given
acosθ+bsinθ=m and asinθbcosθ=n
m2+n2=(asinθ+bsinθ)2+(asinθbsinθ)2

Therefore,
m2+n2=a2cos2θ+b2sin2θ+2abcosθsinθ+a2sin2θ+b2cos2θ2absinθcosθ
m2+n2=(a2+b2)cos2θ+(a2+b2)sin2θ
m2+n2=(a2+b2)

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