Question

If a current of $0.3$ ampere is drawn from a Daniell cell for $1$ hour, what would be the change in mass of electrodes? (At. mass of $Cu=63.5$ and $Zn=65.37)$.

Answer 1

$i=0.3A$

$t=60\times 60sec$

$Q=0.3\times 60\times 60$

$AmountofZnoxidisedorloss=\frac{65.4}{2\times 96500}\times 0.3\times 60\times 60$

$=0.3659g$

$AmountofCureducedgain=\frac{63.5}{2\times 96500}\times 0.3\times 60\times 60$

$=0.23689g$