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Question

If a curve passes through the origin and the slope of the tangent to it at any point (x,y) is x24x+y+8x2, then this curve also passes through the point :

A
(4,5)
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B
(5,4)
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C
(4,4)
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D
(5,5)
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Solution

The correct option is D (5,5)
dydx=(x2)2+y+4(x2)=(x2)+y+4(x2)
Let x2=tdx=dt
and y+4=udy=dudydx=dudtdudt=t+utdudtut=tI.F.=e1tdt=elnt=1tu×1t=t×1tdtut=t+cy+4x2=(x2)+c
Passing through (0,0)
c=0
(y+4)=(x2)2
It passes though (5,5)

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