If a curve satisfies ydx - xdy -3 x 2 y 2 e x 3 dx -0 and y 0-1 then y 1-A- 1-1- eB- 1- eC- 1-e-1D- e -1

The correct option is A d( x/y )+d(e^x3)=0 ⇒ x/y+e^x3=c x = 0, y=1 ⇒ c=1 x = 1 ⇒1/y+e=1 y = 1/1 c ...

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Linear Differential Equations of First Order

If a curve sa...

Question

$I f a c u r v e s a t i s f i e s y d x - x d y + 3 x^{2}$ $y^{2} e^{x^{3}}$ dx = 0 and y(0) = 1 then y(1)=

1 – e

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e – 1

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