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Question

If a curve y=f(x) passes through the point (1,2) and satisfies xdydx+y=bx4, then for what value of b, 21f(x)dx=625 ?

A
5
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B
625
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C
10
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D
315
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Solution

The correct option is C 10
dydx+yx=bx3
I.F. =edxx=x
yx=bx4dx=bx55+c
Above curve passes through (1,2).
2=b5+c (1)

Also, 21(bx45+cx)dx=625
b25×32+cln2b25=625 (2)

Solving (1) and (2),
c=0 and b=10

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