Question

If a cyclist takes a turn of radius $10m$, going at a speed of $10m/s$ then find the angle through which he must bend in order to avoid overturning. [asume $g=10m/s^2$]

• A. ${90}^0$
• B. $0^o$
• C. ${45}^o$
• D. ${30}^o$

Answer 1

The correct option is C ${45}^o$

We know that the angle through which the cyclist should bend is given by $\theta =ta{n}^{-1}\left(\frac{v^2}{Rg}\right)$

Substituting the given values we get $\theta =ta{n}^{-1}\left(\frac{{10}^2}{10\times 10}\right)$

$\Rightarrow$ $\theta =ta{n}^{-1}\left(1\right)$

$\Rightarrow$ $\theta ={45}^o$