If A + D = B + C, A + E = C + D, 2C, < A + E and 2A> B + D then ______________.
A
A > B > C> D>E
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B
B > A > D > C> E
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C
D > B > C > A > E
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D
B > C > D > E > A
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Solution
The correct option is B B > A > D > C> E 2C<A+E,A+E=C+D2C<A+E,A+E=C+D ⇒2C<C+D⇒C<D⇒2C<C+D⇒C<D ...(1) A+D=B+C,C<D⇒A<BA+D=B+C,C<D⇒A<B ...(2) 2A>B+D,A<B⇒A>D2A>B+D,A<B⇒A>D ...(3) A+E=C+D,A>D⇒E<CA+E=C+D,A>D⇒E<C ...(4)