If A + D > C + E, C + D - 2B and B + E > C + D it necessarliy follows that _______________.
A
A + B > 2D
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B
B + D > C+ E
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C
A + D > B + E
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D
A + D > B + C
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Solution
The correct option is D A + D > B + C A+D>C+EA+D>C+E ⇒A+D>(2B−D)+E(∵C+D=2B)⇒A+D>(2B−D)+E(∵C+D=2B) ⇒A+D>(B+E)+(B−D)⇒A+D>(B+E)+(B−D) ⇒A+D>(C+D)+(B−D)⇒A+D>(C+D)+(B−D) ⇒A+D>B+C