If A - B - A - B- thenA- A - BB- A - B-C- A - B -D- A - B-A-B

The correct option is B A∩ B=ϕA Δ B = (A – B) ∪ (B – A) ∵ A Δ B = A ∪ B ⇒ (A∪ (B − A)) − (B ∪ (B − A)) = (A ∪ B) ⇒ (A ∪ B) − (A) − (B) + (A ∪ B) = (A ∪ B ...

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Byju's Answer

Standard XII

Mathematics

Difference of Two Sets

If A Δ B = A ...

Question

If $A Δ B = A \cup B,$ then

A = B

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A \cap B = ϕ

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A Δ B = ϕ

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A Δ B = A - B

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Solution

The correct option is B $A \cap B = ϕ$
$A Δ B = (A - B) \cup (B - A) ∵ A Δ B = A \cup B \Rightarrow (A \cup (B - A)) - (B \cup (B - A)) = (A \cup B) \Rightarrow (A \cup B) - (A) - (B) + (A \cup B) = (A \cup B) \Rightarrow (A \cup B) = (A) + (B) \Rightarrow A \cap B = ϕ$

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If $A \cap B = B$ , then

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A \cap B = ϕ

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If A Δ B=A∪B, then

The correct option is B A∩B=ϕA Δ B=(A–B)∪(B–A)∵A Δ B=A∪B⇒(A∪(B−A))−(B∪(B−A))=(A∪B)⇒(A∪B)−(A)−(B)+(A∪B)=(A∪B)⇒(A∪B)=(A)+(B)⇒A∩B=ϕ

If $A Δ B = A \cup B,$ then

The correct option is B $A \cap B = ϕ$
$A Δ B = (A - B) \cup (B - A) ∵ A Δ B = A \cup B \Rightarrow (A \cup (B - A)) - (B \cup (B - A)) = (A \cup B) \Rightarrow (A \cup B) - (A) - (B) + (A \cup B) = (A \cup B) \Rightarrow (A \cup B) = (A) + (B) \Rightarrow A \cap B = ϕ$