If a denotes the nth term of the AP $2, 7, 12, 17, . . . . .$ , find the value of $(a_{30} - a_{20})$ .

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Solution

Given AP is $2, 7, 12, 17, . . . .$
Here, $a = 2, d = 7 - 2 = 5$
Now,
$a_{n} = a + (n - 1) d = 2 + (n - 1) 5 = 5 n - 3$
$a_{30} = 2 + (30 - 1) 5 = 2 + 145 = 147$ and
$a_{20} = 2 + (20 - 1) 5 = 2 + 95 = 97$
$a_{30} - a_{20} = 147 - 97 = 50$ .

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IF $a_{n}$ denotes the nth term of the AP 2, 7, 12, 17, ..., find the value of $(a_{30} - a_{20})$ .

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(a_{30} - a_{20})

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