You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XIII

Mathematics

Permutation under Restriction

If a denotes ...

Question

If a denotes the number of permutations of (x+2) things taken all at a time, b the number of permutations of x things taken 11 at a time and c the number of permutations of (x – 11) things taken all at a times and a = 182bc, then x =

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 12
$a = ∠ (x + 2), b =^{X} P_{11} = \frac{∠ X}{∠ x - 11},$ $c = ∠ x - 11$ and a = 182bc $\Rightarrow (x + 1) (x + 2) = 182 = 13.14 \Rightarrow x = 12$

Suggest Corrections

Similar questions

Q. If a denotes the number of permutations of (x + 2) things taken all at a time, b the number of permutations of x things taken 11 at a time and c the number of permutations of x − 11 things taken all at a time such that a = 182 bc, find the value of x.

Q. If

a

denotes the number of permutations of

x + 2

things taken all at a time,

b

the number of permutations of

x

things taken

11

at a time and

c

the number of permutations of

x - 11

things taken all at a time such that

a = 182 b c

, then the value of

x

Q. If p denotes the number of permutations of

(x + 3)

things taken all at a time, q denotes the number of permutations of

(x + 1)

things taken 11 at a time and r denotes denotes the number permutations of

(x - 10)

things taken all at a time such that

p = 182 q r,

then the value of x is

If a denotes the number of permutations of (x+2) things taken all at a time, b the number of permutations of x-11 things taken all at a time such that a = 182 bc, find the value of x.

Q. If

a

represents the number of permutations of

(x + 2)

things taken together,

b

represents the number of permutations of

11

things taken together out of

x

things, and

c

represents the number of permutations of

(x - 11)

things taken together so that

a = 182 b c

, then

x =

Join BYJU'S Learning Program

If a denotes the number of permutations of (x+2) things taken all at a time, b the number of permutations of x things taken 11 at a time and c the number of permutations of (x – 11) things taken all at a times and a = 182bc, then x =

The correct option is D 12a=∠(x+2),b=XP11=∠X∠x−11, c=∠x−11 and a = 182bc ⇒(x+1)(x+2)=182=13.14⇒x=12

The correct option is D 12
$a = ∠ (x + 2), b =^{X} P_{11} = \frac{∠ X}{∠ x - 11},$ $c = ∠ x - 11$ and a = 182bc $\Rightarrow (x + 1) (x + 2) = 182 = 13.14 \Rightarrow x = 12$