If a determinant of order $3 \times 3$ is formed by using the numbers 1 or -1 then minimum value of determination is

-2

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-4

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-8

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Solution

The correct option is B -4
let us assume the determinant in this order ,where $x = 1$
$∣ ∣ ∣ ∣ \begin{matrix} x & x & x - x & x & - x x & x & - x \end{matrix} ∣ ∣ ∣ ∣$ (we can put $x$ in any order )
on solving this determinant ,we will get
$D = - 4 x^{3}$
we know $x = 1$ or $- 1$
for minimum value of determinant $x = 1$
hence $D_{m i n} = - 4$

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If a determinant of order 3×3 is formed by using the numbers 1 or -1 then minimum value of determination is

The correct option is B -4let us assume the determinant in this order ,where x=1∣∣ ∣∣xxx−xx−xxx−x∣∣ ∣∣ (we can put x in any order ) on solving this determinant ,we will get D=−4x3we know x=1 or −1for minimum value of determinant x=1 hence Dmin=−4

If a determinant of order $3 \times 3$ is formed by using the numbers 1 or -1 then minimum value of determination is