If A- 3x 4 4 - x 4 2 -5x-7-B- 2x 3 3 - 3x 3 2 - x 6 -C- 2x 4 3 - 3x 4 4 -5Find -AC

Given that, A = 3x^44 x^42 + 5x 7 = x^44 + 5x 7 B = 2x^33 + 3x^32 x6 = 13x^36 x6 C = 2x^43 3x^44 + 5 = x^412 + 5 ( A)C = #160 ...

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Expansion of (x^2 - y^2)

If A= 3x 4 ...

Question

If $A = \frac{{3 x}^{4}}{4} - \frac{x^{4}}{2} + 5 x - 7; B = \frac{{2 x}^{3}}{3} + \frac{{3 x}^{3}}{2} - \frac{x}{6}; C = \frac{{2 x}^{4}}{3} - \frac{{3 x}^{4}}{4} + 5$
Find $(- A) C$

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Solution

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Similar questions

A = \frac{{3 x}^{4}}{4} - \frac{x^{4}}{2} + 5 x - 7; b = \frac{{2 x}^{3}}{3} + \frac{{3 x}^{3}}{2} - \frac{x}{6}; C = \frac{{2 x}^{4}}{3} - \frac{{3 x}^{4}}{4} + 5

- A + B - C

A = \frac{{3 x}^{4}}{4} - \frac{x^{4}}{2} + 5 x - 7; B = \frac{{2 x}^{3}}{3} + \frac{{3 x}^{3}}{2} - \frac{x}{6}; C = \frac{{2 x}^{4}}{3} - \frac{{3 x}^{4}}{4} + 5

- 2 A + 6 B + 3 C

A = \frac{{3 x}^{4}}{4} - \frac{x^{4}}{2} + 5 x - 7; B = \frac{{2 x}^{3}}{3} + \frac{{3 x}^{3}}{2} - \frac{x}{6}; C = \frac{{2 x}^{4}}{3} - \frac{{3 x}^{4}}{4} + 5

B A

A = \frac{{3 x}^{4}}{4} - \frac{x^{4}}{2} + 5 x - 7; B = \frac{{2 x}^{3}}{3} + \frac{{3 x}^{3}}{2} - \frac{x}{6}; C = \frac{{2 x}^{4}}{3} - \frac{{3 x}^{4}}{4} + 5

3 A - 2 B - C

A = \frac{{3 x}^{4}}{4} - \frac{x^{4}}{2} + 5 x - 7; B = \frac{{2 x}^{3}}{3} + \frac{{3 x}^{3}}{2} - \frac{x}{6}; C = \frac{{2 x}^{4}}{3} - \frac{{3 x}^{4}}{4} + 5

\frac{5}{2} C - \frac{4}{3} A - \frac{3 B}{4}

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