If a=sinx×cos3xsin3x×cosx then which of the following is wrong?
A
a<13
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B
a>3
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C
13<a<3
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D
None of these
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Solution
The correct option is D13<a<3 Given, a=sinx×cos3xcosx×sin3x It is not defined for cosx=0 and sin3x=0 ⇒x=(2n+1)π2 and x=nπ Hence defined for the given range: −2π3<x<−π2 or −π3<x<0 Therefore, a<13 or a>3