1
Question
If A=diag[2,−3,−5], B=diag[4,−6,−3] and C=diag[−3,4,1] then find
2A+B−5C
2A+B−5C
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Solution
A=⎡⎢⎣2000−3000−5⎤⎥⎦ B=⎡⎢⎣4000−6000−3⎤⎥⎦ C=⎡⎢⎣−300040001⎤⎥⎦
2A+B−5C=2⎡⎢⎣2000−3000−5⎤⎥⎦+⎡⎢⎣4000−6000−3⎤⎥⎦−5⎡⎢⎣−300040001⎤⎥⎦
2A+B−5C=⎡⎢⎣4000−6000−10⎤⎥⎦+⎡⎢⎣4000−6000−3⎤⎥⎦−⎡⎢⎣−15000200005⎤⎥⎦
2A+B−5C=⎡⎢⎣8000−12000−13⎤⎥⎦−⎡⎢⎣−15000200005⎤⎥⎦
2A+B−5C=⎡⎢⎣23000−32000−18⎤⎥⎦
2A+B−5C=2⎡⎢⎣2000−3000−5⎤⎥⎦+⎡⎢⎣4000−6000−3⎤⎥⎦−5⎡⎢⎣−300040001⎤⎥⎦
2A+B−5C=⎡⎢⎣4000−6000−10⎤⎥⎦+⎡⎢⎣4000−6000−3⎤⎥⎦−⎡⎢⎣−15000200005⎤⎥⎦
2A+B−5C=⎡⎢⎣8000−12000−13⎤⎥⎦−⎡⎢⎣−15000200005⎤⎥⎦
2A+B−5C=⎡⎢⎣23000−32000−18⎤⎥⎦
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