If a diagonal of length 4 divides a parallelogram into 2 triangles in which one triangle has sides equal to 3, 4, 5 in length. Find the perimeter of the parallelogram.(Given parallelogram is not a rectangle)

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Solution

The correct option is C 18
Let the parallelogram be ABCD and the diagonal be AC.
Angle B cannot be $90^{0}$ because it is not a rectangle.
Let $∠$ CAB = $90^{0}$
So, AB = 3 and BC = 5 because length of the diagonal is given as 4.
Perimeter $= 3 + 5 + 3 + 5 = 18$

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