Question

If a diamond has a face-centered cubic structure with two atoms per lattice point and a unit cell of the edge of $3.569\mathring{A}$. The density (in g cm${}^{-3}$) of the diamond is :

• A. $3.569$
• B. $2.569$
• C. $1.899$
• D. $7.946$

Answer 1

The correct option is A $3.569$

Diamond is a carbon allotrope. We can use density formula to calculate the density as follows:

Density $=\rho =\frac{ZM}{N_0{a}^3}$

Substituting values in the above expression, we get $\rho =\frac{2\times 12}{(6.022\times {10}^{23})\times (3.569\times {10}^{-8}{)}^3}$

On solving the above equation, we get $\rho$ as $3.569$ g cm${}^{-3}$.

Hence, the correct option is $\text{A}$