Question

If a dice is thrown twice, then find the probability of getting $1$ in the first throw only.

• A. $\frac{11}{36}$
• B. $\frac{7}{36}$
• C. $\frac{5}{36}$
• D. None of these

Answer 1

The correct option is C $\frac{5}{36}$

Probability of getting $1$ in first throw, $P\left(A\right)=$ $\frac{1}{6}$.
Probability of not getting $1$ in second throw, $P\left(B\right)$ $\frac{5}{6}$.
Both are independent events, so the required probability is
$P\left(AB\right)=P\left(A\right)\times P\left(B\right)=$ $\frac{1}{6}\times \frac{5}{6}$ = $\frac{5}{36}$.