Question

If a dice is tossed once, then the probability of getting a prime number is

• A. $\frac{1}{3}$
• B. $\frac{1}{6}$
• C. $\frac{1}{2}$
• D. $1$

Answer 1

Answer: (C)

$\frac{1}{2}$

Let $S$ be the sample space.

$S=\{1,2,3,4,5,6\}⟹n\left(S\right)=6$

Let $A$ be an event of getting prime numbers

Prime numbers on the dice are $2,3,5⟹A=\{2,3,5\}⟹n\left(A\right)=3$

Then, $P\left(A\right)=\frac{n\left(A\right)}{n\left(S\right)}=\frac{3}{6}=\frac{1}{2}$
Hence, Probability of getting prime numbers $=\frac{1}{2}$