If A=∣∣∣24k−2∣∣∣ and A2=0 then find the value of k
A
-4
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B
-3
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C
-2
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D
-1
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Solution
The correct option is D -1 A2=0 =>∣∣∣24k−2∣∣∣×∣∣∣24k−2∣∣∣=∣∣∣0000∣∣∣ ∣∣∣2(2)+4(k)2(4)+4(−2)k(2)+(−2)(k)k(4)+(−2)(−2)∣∣∣=∣∣∣0000∣∣∣ ∣∣∣4k+4004k+4∣∣∣=∣∣∣0000∣∣∣ =>4k+4=0 =>k=−1