wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If acosθ+bsinθ=m and asinθbcosθ=n then, a2+b2 equals

A
m+n
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
mn
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
mn
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
m2+n2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is B m2+n2
a cosθ+bsinθ=m and asinθbcosθ=n
m2+n2=(acosθ+bsinθ)2+(asinθbcosθ)2
m2+n2=a2cos2θ+b2sin2θ+2absinθcosθ+a2sin2θ+b2cos2θ2absinθcosθ
m2+n2=a2(sin2θ+cos2θ)+b2(sin2θ+cos2θ)
m2+n2=a2+b2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Trigonometric Identities_Concept
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon