If a - 1-a - 2- then a2 - 1-a2 will be equal to

The correct option is A 6Given, a 1/a = 2 On squaring both sides, we get a^2+1/a^2 2× a×1/a=4 ⇒ a^2+1/a^2 2=4 ⇒ a^2+1/a^2=6 Hence, Option A ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Properties of Conjugate of a Complex Number

If a - 1/a ...

Question

If $a - \frac{1}{a} = 2$ , then $a^{2} + \frac{1}{a^{2}}$ will be equal to

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

a^{2} + \frac{1}{a^{2}}

a - \frac{1}{a}

a^{2} + \frac{1}{a^{2}}

a + \frac{1}{a}

y = \frac{x}{\sqrt{a^{2} - 1}} - \frac{2}{\sqrt{a^{2} - 1}} {tan}^{- 1} (\frac{sin x}{a + \sqrt{a^{2} - 1} + cos x})

a \in (- \infty, - 1) \cup (1, \infty),

y^{'} (\frac{π}{2})

a_{1}, a_{2}, a_{3}, . . . . a_{n}

a_{1} a_{2} + a_{2} a_{3} + . . . . . + a_{n - 1} a_{n}

(1 + i) (1 + 2 i) (1 + 3 i) . . . (1 + n i) = a + i b, then 2 \times 5 \times 10 \times . . . . \times (1 + n^{2})

\sqrt{a^{2} + b^{2}}

\sqrt{a^{2} - b^{2}}

a^{2} + b^{2}

a^{2} - b^{2}

a + b

Join BYJU'S Learning Program