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Question

If A=10et1+tdt then 10etln(1+t)dt=

A
e ln2A
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B
e ln2+A
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C
Ae ln2
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D
A ln2
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Solution

The correct option is A e ln2A
A=10et1+tdt
Now,
10etln(1+t)dt
Integrating by parts taking ln(1+t) as the first function.
=[ln(1+t)et]101011+t×etdt
=eln2A

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