If A=1+rz+r2z+r3z+....∞, then the value of r will be
A(1-A)z
A-1A1Z
1A-11Z
A(1-A)1Z
Find the value of r :
Given, A=1+rz+r2z+r3z+....∞
This is a G.P
Here, a=1
common ratio, r=rz
⇒A=11-rz ∵S∞=a1-r
⇒A-Arz=1
⇒Arz=A-1
⇒rz=A-1A
∴r=(A-1A)1Z
Hence, Option ‘B’ is Correct.
If r>1 and x=a+ar+ar2 y=b+br+br2 z=c+cr+cr2,
then the value of xyz2 is ___.
If L=limn→∞∞∫andx1+n2x2, where a∈R, then the value of L can be