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Question

If A=tan-1(x), then sin2A =


A

2x1-x2

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B

2a1-x2

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C

2x1+x2

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D

Noneofthese

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Solution

The correct option is C

2x1+x2


Finding the value:

Given,

A=tan-1(x)tanA=x

Also we know,

sin2A=2tanA1+tan2A

Now put the value of tanA=x

sin2A=2Γ—x1+x2β‡’sin2A=2x1+x2

Hence the correct option is(B)


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