If a first order reaction takes 32 minutes for 75% completion, then time required for 50% completion is :
A
32 min
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
16 min
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
8 min
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4 min
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 16 min k=2.303tlog(aa−x)
When, a = 100, x = 75, t = 32 k=2.30332log10(100100−75) k=2.30332log10(10025)=0.0433min−1
Time for 50% completion (t1/2)=0.693k=0.6930.0433≈16min
Thus option (b) is correct